PrecalculusSuperchallengeIntroduction to Limits ShareIntroduction to Limits · Superchallenge problemEvaluate limx→1x−1x3−1\displaystyle\lim_{x\to1}\frac{\sqrt{x}-1}{\sqrt[3]{x}-1}x→1lim3x−1x−1. (Hint: substitute x=t6x=t^{6}x=t6.)Check Show answer Walk through it step by step Practice more like this Review this concept