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GeometrySuperchallengeOlympiad Geometry

Olympiad Geometry · Superchallenge problem

DABC40°

In △ABC\triangle ABC, point DD lies on BC‾\overline{BC} so that AD=BDAD = BD and AC=DCAC = DC. If m∠C=40∘m\angle C = 40^\circ, find m∠BACm\angle BAC.