GeometrySuperchallengeOlympiad Geometry ShareOlympiad Geometry · Superchallenge problemDABC40°In △ABC\triangle ABC△ABC, point DDD lies on BC‾\overline{BC}BC so that AD=BDAD = BDAD=BD and AC=DCAC = DCAC=DC. If m∠C=40∘m\angle C = 40^\circm∠C=40∘, find m∠BACm\angle BACm∠BAC.Check Show answer Walk through it step by step Practice more like this Review this concept