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Olympiad Geometry · Superchallenge problem

JABC70°

In △ABC\triangle ABC, the bisector of interior angle ∠ABC\angle ABC and the bisector of the exterior angle at CC meet at point JJ. If m∠BJC=23∘m\angle BJC = 23^\circ and m∠ABC=70∘m\angle ABC = 70^\circ, find m∠ACBm\angle ACB.