GeometrySuperchallengeOlympiad Geometry ShareOlympiad Geometry · Superchallenge problemDEABC30°In △ABC\triangle ABC△ABC, AB=ACAB = ACAB=AC. Point DDD lies on BC‾\overline{BC}BC with m∠BAD=30∘m\angle BAD = 30^\circm∠BAD=30∘, and point EEE lies on AC‾\overline{AC}AC with AE=ADAE = ADAE=AD. Find m∠EDCm\angle EDCm∠EDC.Check Show answer Walk through it step by step Practice more like this Review this concept