GeometryHardOlympiad Geometry ShareOlympiad Geometry · Hard problemIn △ABC\triangle ABC△ABC, the bisector of ∠A\angle A∠A meets BC‾\overline{BC}BC at DDD. If m∠B=80∘m\angle B = 80^\circm∠B=80∘ and m∠ADB=55∘m\angle ADB = 55^\circm∠ADB=55∘, find m∠Cm\angle Cm∠C.Check Show answer Walk through it step by step Practice more like this Review this concept