GeometryHardOlympiad Geometry ShareOlympiad Geometry · Hard problemABCD40°△ABC\triangle ABC△ABC is equilateral. Point DDD is on the opposite side of line BCBCBC from AAA, with DB=DCDB = DCDB=DC and m∠BDC=40∘m\angle BDC = 40^\circm∠BDC=40∘. Find m∠ABDm\angle ABDm∠ABD.Check Show answer Walk through it step by step Practice more like this Review this concept