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GeometryHardOlympiad Geometry

Olympiad Geometry · Hard problem

DABC40°30°

In △ABC\triangle ABC, point DD lies on BC‾\overline{BC} with AD=ABAD = AB. If m∠BAD=40∘m\angle BAD = 40^\circ and m∠DAC=30∘m\angle DAC = 30^\circ, find m∠Cm\angle C.