GeometryHardOlympiad Geometry ShareOlympiad Geometry · Hard problemDABC40°30°In △ABC\triangle ABC△ABC, point DDD lies on BC‾\overline{BC}BC with AD=ABAD = ABAD=AB. If m∠BAD=40∘m\angle BAD = 40^\circm∠BAD=40∘ and m∠DAC=30∘m\angle DAC = 30^\circm∠DAC=30∘, find m∠Cm\angle Cm∠C.Check Show answer Walk through it step by step Practice more like this Review this concept