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GeometryChallengeOlympiad Geometry

Olympiad Geometry · Challenge problem

PABC20°25°

Point PP lies inside △ABC\triangle ABC with PA=PB=PCPA = PB = PC. If m∠PAB=20∘m\angle PAB = 20^\circ and m∠PBC=25∘m\angle PBC = 25^\circ, find m∠PCAm\angle PCA.