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GeometryChallengeOlympiad Geometry

Olympiad Geometry · Challenge problem

ABCDE110°

In △ABC\triangle ABC, m∠BAC=110∘m\angle BAC = 110^\circ. The perpendicular bisector of AB‾\overline{AB} meets BC‾\overline{BC} at DD, and the perpendicular bisector of AC‾\overline{AC} meets BC‾\overline{BC} at EE. Find m∠DAEm\angle DAE.