TrigonometryHardThe Unit Circle and Circular Functions ShareThe Unit Circle and Circular Functions · Hard problemEvaluate exactly: sec25π6−tan27π3+csc(−π6)\sec^2\dfrac{5\pi}{6} - \tan^2\dfrac{7\pi}{3} + \csc\left(-\dfrac{\pi}{6}\right)sec265π−tan237π+csc(−6π).Check Show answer Walk through it step by step Practice more like this Review this concept