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TrigonometryHardThe Unit Circle and Circular Functions

The Unit Circle and Circular Functions · Hard problem

Evaluate exactly: sec⁡25π6−tan⁡27π3+csc⁡(−π6)\sec^2\dfrac{5\pi}{6} - \tan^2\dfrac{7\pi}{3} + \csc\left(-\dfrac{\pi}{6}\right).