GeometryHardOlympiad Geometry ShareOlympiad Geometry · Hard problemIn △ABC\triangle ABC△ABC, AB=10AB = 10AB=10 and AC=15AC = 15AC=15. The bisector of ∠A\angle A∠A meets BC‾\overline{BC}BC at DDD. If BD=8BD = 8BD=8, find DCDCDC.Check Show answer Walk through it step by step Practice more like this Review this concept