GeometryChallengeOlympiad Geometry ShareOlympiad Geometry · Challenge problemABCDE415129Triangle ABCABCABC has AB=9AB = 9AB=9, AC=12AC = 12AC=12 and BC=15BC = 15BC=15. Point DDD lies on AB‾\overline{AB}AB with AD=4AD = 4AD=4, and point EEE lies on AC‾\overline{AC}AC so that △ADE∼△ACB\triangle ADE \sim \triangle ACB△ADE∼△ACB (with A→AA \to AA→A, D→CD \to CD→C, E→BE \to BE→B). Find DEDEDE.Check Show answer Walk through it step by step Practice more like this Review this concept