GeometryHardOlympiad Geometry ShareOlympiad Geometry · Hard problemIn △ABC\triangle ABC△ABC, point DDD is on AB‾\overline{AB}AB and point EEE is on AC‾\overline{AC}AC. We know m∠ADE=(3x+5)∘m\angle ADE = (3x + 5)^\circm∠ADE=(3x+5)∘, m∠ABC=(4x−10)∘m\angle ABC = (4x - 10)^\circm∠ABC=(4x−10)∘, and m∠AED=58∘m\angle AED = 58^\circm∠AED=58∘. If DE‾∥BC‾\overline{DE} \parallel \overline{BC}DE∥BC, find m∠Am\angle Am∠A.Check Show answer Walk through it step by step Practice more like this Review this concept