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PrecalculusSuperchallengeIntroduction to Limits

Introduction to Limits · Superchallenge problem

Using lim⁡u→0sin⁡uu=1\displaystyle\lim_{u \to 0}\frac{\sin u}{u} = 1, evaluate lim⁡x→∞x(π2−arctan⁡x)\displaystyle\lim_{x \to \infty} x\left(\frac{\pi}{2} - \arctan x\right).