Algebra 1ChallengeExponents ShareExponents · Challenge problemThe numbers xxx and yyy satisfy 2x⋅4y=1282^{x}\cdot 4^{y} = 1282x⋅4y=128 and 27x9y=3\dfrac{27^{x}}{9^{y}} = 39y27x=3. Find x+yx + yx+y.Check Show answer Walk through it step by step Practice more like this Review this concept