Exponents

Study Sheet

Exponents

Every rule, tip, and worked example in one place

What an Exponent Means

Concept
Repeated Multiplication

An exponent is a shortcut for repeated multiplication. In the power ana^{n}:

  • aa is the base --- the number being multiplied.
  • nn is the exponent (or power) --- how many times the base is used as a factor.
an=aaaan factors,25=22222=32.a^{n} = \underbrace{a \cdot a \cdot a \cdots a}_{n \text{ factors}}, \qquad 2^{5} = 2\cdot 2\cdot 2\cdot 2\cdot 2 = 32.

We read ana^{n} as “aa to the nnth power.” Special names: a2a^{2} is “aa squared” and a3a^{3} is “aa cubed.”

Example
Expanding and evaluating

Write each power as repeated multiplication, then evaluate.

34=3333=81,(2)3=(2)(2)(2)=8,(12)3=121212=18.\begin{aligned} 3^{4} &= 3\cdot 3\cdot 3\cdot 3 = 81, \\[2pt] (-2)^{3} &= (-2)(-2)(-2) = -8, \\[2pt] \left(\tfrac{1}{2}\right)^{3} &= \tfrac{1}{2}\cdot\tfrac{1}{2}\cdot\tfrac{1}{2} = \tfrac{1}{8}. \end{aligned}
Tip

Watch the sign carefully: (2)4=16(-2)^{4} = 16 (four negatives multiply to a positive), but 24=(24)=16-2^{4} = -(2^{4}) = -16, because without parentheses the exponent applies only to the 22, and the minus sign waits out front.

All the Exponent Rules at a Glance

Concept
The Complete Rule Sheet

For any nonzero base(s) aa, bb and integers mm, nn:

  • Product of powers: aman=am+na^{m}\cdot a^{n} = a^{m+n}
  • Quotient of powers: aman=amn\dfrac{a^{m}}{a^{n}} = a^{m-n}
  • Power of a power: (am)n=amn\left(a^{m}\right)^{n} = a^{mn}
  • Power of a product: (ab)n=anbn\left(ab\right)^{n} = a^{n}b^{n}
  • Power of a quotient: (ab)n=anbn\left(\dfrac{a}{b}\right)^{n} = \dfrac{a^{n}}{b^{n}}
  • Zero exponent: a0=1a^{0} = 1
  • Negative exponent: an=1ana^{-n} = \dfrac{1}{a^{n}}   and   1an=an\dfrac{1}{a^{-n}} = a^{n}

The whole topic comes back to one idea: same base, combine the exponents.

Product of Powers

Concept
Add the Exponents

When you multiply powers with the same base, keep the base and add the exponents.

aman=am+n.a^{m}\cdot a^{n} = a^{m+n}.

Why? a2a3=(aa)(aaa)=a5a^{2}\cdot a^{3} = (a\cdot a)(a\cdot a\cdot a) = a^{5}: you are just counting all the factors.

Example
Multiplying like bases
x4x3=x4+3=x7,2522=27=128,5a23a6=(53)a2+6=15a8.\begin{aligned} x^{4}\cdot x^{3} &= x^{4+3} = x^{7}, \\[2pt] 2^{5}\cdot 2^{2} &= 2^{7} = 128, \\[2pt] 5a^{2}\cdot 3a^{6} &= (5\cdot 3)\,a^{2+6} = 15a^{8}. \end{aligned}

Multiply the coefficients (the plain numbers) and add the exponents of the matching variables.

Tip

The bases must match. You cannot combine x3y2x^{3}\cdot y^{2} into a single power --- different bases stay separate.

Quotient of Powers

Concept
Subtract the Exponents

When you divide powers with the same base, keep the base and subtract the bottom exponent from the top.

aman=amn.\frac{a^{m}}{a^{n}} = a^{m-n}.

The shared factors cancel: a5a2=aaaaaaa=a3\dfrac{a^{5}}{a^{2}} = \dfrac{a\cdot a\cdot a\cdot a\cdot a}{a\cdot a} = a^{3}.

Example
Dividing like bases
x9x4=x94=x5,3735=32=9,12b84b3=124b83=3b5.\begin{aligned} \frac{x^{9}}{x^{4}} &= x^{9-4} = x^{5}, \\[4pt] \frac{3^{7}}{3^{5}} &= 3^{2} = 9, \\[4pt] \frac{12b^{8}}{4b^{3}} &= \frac{12}{4}\,b^{8-3} = 3b^{5}. \end{aligned}
Tip

Top minus bottom --- order matters. a2a6=a26=a4=1a4\dfrac{a^{2}}{a^{6}} = a^{2-6} = a^{-4} = \dfrac{1}{a^{4}}. A negative result just means the base “lives” in the denominator.

Power of a Power

Concept
Multiply the Exponents

When a power is raised to another power, keep the base and multiply the exponents.

(am)n=amn.\left(a^{m}\right)^{n} = a^{mn}.

Because (a2)3=a2a2a2=a6\left(a^{2}\right)^{3} = a^{2}\cdot a^{2}\cdot a^{2} = a^{6}.

Example
Raising a power to a power
(x3)4=x34=x12,(22)3=26=64,(y5)2=y10.\begin{aligned} \left(x^{3}\right)^{4} &= x^{3\cdot 4} = x^{12}, \\[2pt] \left(2^{2}\right)^{3} &= 2^{6} = 64, \\[2pt] \left(y^{5}\right)^{2} &= y^{10}. \end{aligned}
Tip

Do not confuse the rules: (x3)4=x12\left(x^{3}\right)^{4} = x^{12} (multiply), but x3x4=x7x^{3}\cdot x^{4} = x^{7} (add). Ask yourself whether the powers are being multiplied together or stacked.

Power of a Product and Power of a Quotient

Concept
Distribute the Exponent

An exponent on a product or a quotient applies to every factor inside.

(ab)n=anbn,(ab)n=anbn.\left(ab\right)^{n} = a^{n}b^{n}, \qquad \left(\frac{a}{b}\right)^{n} = \frac{a^{n}}{b^{n}}.
Example
Distributing over products and quotients
(2x)3=23x3=8x3,(3a2b)2=32a22b2=9a4b2,(x4)2=x242=x216.\begin{aligned} \left(2x\right)^{3} &= 2^{3}x^{3} = 8x^{3}, \\[4pt] \left(3a^{2}b\right)^{2} &= 3^{2}\,a^{2\cdot 2}\,b^{2} = 9a^{4}b^{2}, \\[4pt] \left(\frac{x}{4}\right)^{2} &= \frac{x^{2}}{4^{2}} = \frac{x^{2}}{16}. \end{aligned}

Notice how power of a product combines with power of a power: each inside exponent gets multiplied by the outside one.

Tip

The coefficient gets the exponent too! A common slip is (2x)3=2x3\left(2x\right)^{3} = 2x^{3}. The correct result is 8x38x^{3}, because 23=82^{3} = 8.

Zero and Negative Exponents

Concept
The Zero Exponent

Any nonzero base raised to the 00 power equals 11:

a0=1(a0).a^{0} = 1 \quad (a \ne 0).

This follows from the quotient rule: a3a3=a33=a0\dfrac{a^{3}}{a^{3}} = a^{3-3} = a^{0}, and any number divided by itself is 11.

Reminder — The differentiation rules:(xn)=nxn1,(fg)=fg+fg,(fg)=fgfgg2,(f(g(x)))=f(g(x))g(x)(x^{n})'=nx^{n-1},\quad (fg)'=f'g+fg',\quad \left(\tfrac{f}{g}\right)'=\frac{f'g-fg'}{g^{2}},\quad \big(f(g(x))\big)'=f'(g(x))g'(x)
Concept
Negative Exponents

A negative exponent means take the reciprocal (flip it), then use the positive exponent:

an=1an,1an=an.a^{-n} = \frac{1}{a^{n}}, \qquad \frac{1}{a^{-n}} = a^{n}.

A factor moves between numerator and denominator by flipping the sign of its exponent.

Example
Working with zero and negative exponents
70=1,(5x)0=1,23=123=18,x4=1x4,132=32=9,2x3=2x3.\begin{aligned} 7^{0} &= 1, & (5x)^{0} &= 1, \\[2pt] 2^{-3} &= \frac{1}{2^{3}} = \frac{1}{8}, & x^{-4} &= \frac{1}{x^{4}}, \\[4pt] \frac{1}{3^{-2}} &= 3^{2} = 9, & \frac{2}{x^{-3}} &= 2x^{3}. \end{aligned}
Tip

A negative exponent does not make the answer negative. 23=182^{-3} = \tfrac{1}{8}, a positive number, not 8-8. The exponent's sign controls where the factor goes (top or bottom), not the sign of the value. And remember a0=1a^{0} = 1, never 00.

Simplifying Combined Expressions

Concept
A Game Plan

Real problems mix several rules. A reliable order:

  • Apply power-of-a-power / power-of-a-product to clear outer exponents.
  • Multiply (add exponents) and divide (subtract exponents) like bases.
  • Rewrite any negative exponents as positive by flipping their factors.
  • Simplify the number coefficients.

A fully simplified answer usually has no negative exponents and each base appearing once.

Example
Combining several rules

Simplify   (2x2y)34x4y\;\dfrac{\left(2x^{2}y\right)^{3}}{4x^{4}y}.

(2x2y)34x4y=23x6y34x4ypower of a product=8x6y34x4y23=8=84x64y31quotient rule=2x2y2.\begin{aligned} \frac{\left(2x^{2}y\right)^{3}}{4x^{4}y} &= \frac{2^{3}x^{6}y^{3}}{4x^{4}y} && \text{power of a product} \\[4pt] &= \frac{8x^{6}y^{3}}{4x^{4}y} && 2^{3}=8 \\[4pt] &= \frac{8}{4}\,x^{6-4}\,y^{3-1} && \text{quotient rule} \\[4pt] &= 2x^{2}y^{2}. \end{aligned}
Example
Clearing negative exponents

Simplify   6a2b33a2b1\;\dfrac{6a^{-2}b^{3}}{3a^{2}b^{-1}} with only positive exponents.

6a2b33a2b1=63a22b3(1)quotient rule=2a4b4=2b4a4.move a4 down\begin{aligned} \frac{6a^{-2}b^{3}}{3a^{2}b^{-1}} &= \frac{6}{3}\,a^{-2-2}\,b^{3-(-1)} && \text{quotient rule} \\[4pt] &= 2a^{-4}b^{4} \\[4pt] &= \frac{2b^{4}}{a^{4}}. && \text{move } a^{-4}\text{ down} \end{aligned}
Tip

When subtracting a negative exponent, be careful: b3(1)=b3+1=b4b^{3-(-1)} = b^{3+1} = b^{4}. Two minus signs make a plus.

Scientific Notation

Concept
The Form

Scientific notation writes a number as

c×10n,where 1c<10 and n is an integer.c \times 10^{n}, \qquad \text{where } 1 \le c < 10 \text{ and } n \text{ is an integer.}

The factor cc (the coefficient) has exactly one nonzero digit before the decimal point. The power of 1010 records how far the decimal point moved.

  • Large numbers use a positive exponent: 4300=4.3×1034\,300 = 4.3\times 10^{3}.
  • Small numbers (between 00 and 11) use a negative exponent: 0.0057=5.7×1030.0057 = 5.7\times 10^{-3}.
Example
Converting to and from standard form

To scientific notation --- move the decimal so one nonzero digit stays in front, and count the moves:

52000=5.2×104moved left 4 places0.00081=8.1×104moved right 4 places\begin{aligned} 52\,000 &= 5.2\times 10^{4} && \text{moved left 4 places} \\ 0.00081 &= 8.1\times 10^{-4} && \text{moved right 4 places} \end{aligned}

To standard form --- move the decimal the number of places the exponent says (right if positive, left if negative):

3.6×105=360000,9.2×103=0.0092.\begin{aligned} 3.6\times 10^{5} &= 360\,000, \\ 9.2\times 10^{-3} &= 0.0092. \end{aligned}
Concept
Multiplying and Dividing in Scientific Notation

Handle the coefficients and the powers of 1010 separately, using the product and quotient rules on the 1010's.

(a×10m)(b×10n)=(ab)×10m+n,\left(a\times 10^{m}\right)\left(b\times 10^{n}\right) = (a\cdot b)\times 10^{m+n},
a×10mb×10n=ab×10mn.\frac{a\times 10^{m}}{b\times 10^{n}} = \frac{a}{b}\times 10^{m-n}.

At the end, adjust so the coefficient again satisfies 1c<101 \le c < 10.

Example
Multiplying in scientific notation

Compute (3×104)(2×105)\left(3\times 10^{4}\right)\left(2\times 10^{5}\right).

(3×104)(2×105)=(32)×104+5=6×109.\begin{aligned} \left(3\times 10^{4}\right)\left(2\times 10^{5}\right) &= (3\cdot 2)\times 10^{4+5} \\ &= 6\times 10^{9}. \end{aligned}
Example
Dividing, then fixing the coefficient

Compute 8.4×1074×103\dfrac{8.4\times 10^{7}}{4\times 10^{3}} and 1.5×1035×106\dfrac{1.5\times 10^{3}}{5\times 10^{6}}.

8.4×1074×103=8.44×1073=2.1×104.1.5×1035×106=0.3×103=3×104.\begin{aligned} \frac{8.4\times 10^{7}}{4\times 10^{3}} &= \frac{8.4}{4}\times 10^{7-3} = 2.1\times 10^{4}. \\[6pt] \frac{1.5\times 10^{3}}{5\times 10^{6}} &= 0.3\times 10^{-3} = 3\times 10^{-4}. \end{aligned}

In the second one, 0.30.3 is too small, so we rewrite 0.3=3×1010.3 = 3\times 10^{-1}, which drops the power of 1010 by one.

Tip

If your coefficient ends up 1010 or larger, shift the decimal left and add 11 to the exponent. If it ends up less than 11, shift right and subtract 11. Example: 12×105=1.2×10612\times 10^{5} = 1.2\times 10^{6}.

Exponential Growth vs. Decay (Intro)

Concept
The Pattern y=abxy = a\cdot b^{x}

Many real situations follow

y=abx,y = a\cdot b^{x},

where aa is the starting amount (the value when x=0x=0) and bb is the growth factor. The value of bb decides the behavior:

  • Growth: b>1b > 1 --- the quantity gets larger as xx increases (doubling, tripling, interest).
  • Decay: 0<b<10 < b < 1 --- the quantity gets smaller as xx increases (halving, cooling, fading).

Because b0=1b^{0}=1, the starting value is always y=ab0=ay = a\cdot b^{0} = a.

Example
Evaluating a growth model

A colony starts at 55 bacteria and doubles each hour: y=52xy = 5\cdot 2^{x}, with xx in hours. Here b=2>1b = 2 > 1, so it is growth.

x=0:y=520=51=5,x=1:y=521=10,x=3:y=523=58=40.\begin{aligned} x=0:\quad y &= 5\cdot 2^{0} = 5\cdot 1 = 5, \\ x=1:\quad y &= 5\cdot 2^{1} = 10, \\ x=3:\quad y &= 5\cdot 2^{3} = 5\cdot 8 = 40. \end{aligned}
Example
Evaluating a decay model

A ball bounces to 12\tfrac{1}{2} its previous height, starting at 8080 cm: y=80(12)xy = 80\cdot\left(\tfrac{1}{2}\right)^{x}. Here b=12b = \tfrac{1}{2}, and 0<b<10 < b < 1, so it is decay.

x=0:y=80(12)0=80,x=1:y=8012=40,x=2:y=8014=20.\begin{aligned} x=0:\quad y &= 80\cdot\left(\tfrac{1}{2}\right)^{0} = 80, \\ x=1:\quad y &= 80\cdot\tfrac{1}{2} = 40, \\ x=2:\quad y &= 80\cdot\tfrac{1}{4} = 20. \end{aligned}
Tip

Read bb to tell the story: b>1b>1 means the amount multiplies up (growth); 0<b<10<b<1 means it shrinks toward zero (decay). Either way, plug in xx and use your exponent skills to evaluate.

Going Deeper: Advanced Exponents

Concept
Solving Exponential Equations by Matching Bases

If two powers with the same base are equal, then their exponents must be equal:

bm=bnm=n(b>0, b1).b^{m} = b^{n} \quad\Longrightarrow\quad m = n \qquad (b>0,\ b\ne 1).

To solve an equation like b=Nb^{\,\square} = N, rewrite both sides as powers of one common base, then set the exponents equal and solve that (usually linear) equation.

  • Ask: “What base makes both sides simple?” Often it is the smaller of the two numbers.
  • Use the power-of-a-power rule to fold the outside exponent in: (bk)x=bkx\left(b^{k}\right)^{x} = b^{kx}.
Example
Matching bases to solve

Solve each equation for xx.

2x=322x=25x=5.9x=27(32)x=3332x=33,  2x=3,  x=32.5x+1=1255x+1=53x+1=3,  x=2.\begin{aligned} 2^{x} &= 32 &&\Rightarrow&& 2^{x} = 2^{5} &&\Rightarrow&& x = 5. \\[4pt] 9^{x} &= 27 &&\Rightarrow&& \left(3^{2}\right)^{x} = 3^{3} &&\Rightarrow&& 3^{2x}=3^{3},\ \ 2x=3,\ \ x=\tfrac{3}{2}. \\[4pt] 5^{\,x+1} &= 125 &&\Rightarrow&& 5^{\,x+1} = 5^{3} &&\Rightarrow&& x+1 = 3,\ \ x = 2. \end{aligned}

Each time: write both sides with the same base, then just compare exponents.

Concept
Rational Exponents: the Bridge to Radicals

A fractional exponent is a compact way to write a root. For a0a \ge 0 and positive integers m,nm,n:

a1/n=an,am/n=amn=(an)m.a^{1/n} = \sqrt[n]{a}, \qquad a^{m/n} = \sqrt[n]{a^{m}} = \left(\sqrt[n]{a}\right)^{m}.

Read the fraction as “root on the bottom, power on the top”: the denominator nn is the index of the radical, and the numerator mm is the ordinary power. You may take the root first or the power first --- the answer is the same, but taking the root first keeps the numbers small.

Example
Rational exponents both ways

Evaluate, taking the root first.

82/3=(83)2=22=4,163/4=(164)3=23=8,271/3=1271/3=1273=13.\begin{aligned} 8^{2/3} &= \left(\sqrt[3]{8}\right)^{2} = 2^{2} = 4, \\[4pt] 16^{3/4} &= \left(\sqrt[4]{16}\right)^{3} = 2^{3} = 8, \\[4pt] 27^{-1/3} &= \frac{1}{27^{1/3}} = \frac{1}{\sqrt[3]{27}} = \frac{1}{3}. \end{aligned}

The last one combines two ideas: the negative sign flips it, and the 1/31/3 takes a cube root.

Tip

All the ordinary exponent rules still work with fractional exponents. For instance aa3=a1/2a1/3=a1/2+1/3=a5/6\sqrt{a}\cdot\sqrt[3]{a} = a^{1/2}\cdot a^{1/3} = a^{1/2+1/3} = a^{5/6}. Rewriting radicals as powers is often the fastest way to combine them.

Concept
Comparing Powers of Different Bases

You cannot just eyeball which of 2402^{40} or 3303^{30} is larger. The trick is to make either the exponents match or the bases match, then compare.

  • Match the exponents: factor the exponents to pull out a common one, then compare the resulting bases.
  • Match the bases: rewrite both as powers of a shared base when possible.

Once one part agrees, the larger base (or larger exponent) wins.

Example
Which power is bigger?

Compare 2402^{40} and 3303^{30} by giving them a common exponent of 1010.

240=(24)10=1610,330=(33)10=2710.\begin{aligned} 2^{40} &= \left(2^{4}\right)^{10} = 16^{10}, \\[4pt] 3^{30} &= \left(3^{3}\right)^{10} = 27^{10}. \end{aligned}

Both are raised to the 1010th power, and 27>1627 > 16, so 2710>161027^{10} > 16^{10}. Therefore 330>2403^{30} > 2^{40}.

Concept
Units-Digit Cycles

The units digit (last digit) of a power repeats in a short cycle as the exponent grows, because only the previous units digit affects the next one. For base 77:

71 ⁣= ⁣7,72 ⁣= ⁣49,73 ⁣= ⁣343,74 ⁣= ⁣2401,75 ⁣= ⁣16807, 7^{1}\!=\!7,\quad 7^{2}\!=\!49,\quad 7^{3}\!=\!343,\quad 7^{4}\!=\!2401,\quad 7^{5}\!=\!16807,\ \dots

so the units digits run 7,9,3,1,7,9,3,1,7,\,9,\,3,\,1,\,7,\,9,\,3,\,1,\dots --- a cycle of length 44. To find the units digit of 7k7^{k}, divide kk by the cycle length and use the remainder to pick the spot in the cycle (a remainder of 00 lands on the last entry).

Example
Finding a units digit

Find the units digit of 71007^{100}.

Cycle of units digits: 7,9,3,1(length 4).100÷4=25 remainder 0  use the 4th (last) entry.Units digit of 7100=1.\begin{aligned} &\text{Cycle of units digits: } 7,\,9,\,3,\,1 \quad(\text{length }4). \\[2pt] &100 \div 4 = 25 \text{ remainder } 0 \ \Rightarrow\ \text{use the 4th (last) entry.} \\[2pt] &\text{Units digit of } 7^{100} = 1. \end{aligned}

Check the idea on a small case: 1000(mod4)100 \equiv 0 \pmod 4 matches 74=24017^{4}=2401, which indeed ends in 11.

Concept
Growth and Decay by a Percent Rate

The model y=abxy = a\cdot b^{x} often comes from a percent change per step. Writing the growth factor as b=1±rb = 1 \pm r (with rr a decimal rate) separates the two cases:

Growth: y=a(1+r)x,Decay: y=a(1r)x.\text{Growth: } y = a\,(1+r)^{x}, \qquad \text{Decay: } y = a\,(1-r)^{x}.

Here aa is the starting amount and rr is the rate per period. Growth uses 1+r>11+r>1; decay uses 1r1-r between 00 and 11.

Example
A percent-growth model

A $2000 investment grows 5%5\% per year, so r=0.05r = 0.05 and b=1.05b = 1.05:

y=2000(1.05)x.y = 2000\,(1.05)^{x}.
x=0:y=2000(1.05)0=2000,x=1:y=2000(1.05)1=2100,x=2:y=2000(1.05)2=2000(1.1025)=2205.\begin{aligned} x=0:\quad y &= 2000\,(1.05)^{0} = 2000, \\ x=1:\quad y &= 2000\,(1.05)^{1} = 2100, \\ x=2:\quad y &= 2000\,(1.05)^{2} = 2000\,(1.1025) = 2205. \end{aligned}

A 12%12\% decay would instead use b=10.12=0.88b = 1 - 0.12 = 0.88.

Concept
The Logarithm: Undoing an Exponent (Preview)

Exponentiation asks “what do I get when I raise bb to the power xx?” The logarithm asks the reverse: “what power of bb gives me yy?” They are inverse operations:

bx=ylogby=x(b>0, b1).b^{x} = y \quad\Longleftrightarrow\quad \log_{b} y = x \qquad (b>0,\ b\ne 1).

So logby\log_{b} y is simply the exponent you would put on bb to land on yy. For example, log28=3\log_{2} 8 = 3 because 23=82^{3}=8, and log101000=3\log_{10} 1000 = 3 because 103=100010^{3}=1000. This is the tool that solves 2x=102^{x}=10, where the bases cannot be matched by hand.

Concept
Adding and Subtracting in Scientific Notation

For multiplying and dividing you handle the coefficients and the powers of 1010 separately. But to add or subtract, the powers of 1010 must first match. Rewrite the smaller-exponent number so both share the larger exponent, then add or subtract the coefficients:

a×10n±b×10n=(a±b)×10n.a\times 10^{n} \pm b\times 10^{n} = (a \pm b)\times 10^{n}.

Finally, adjust the coefficient back into the range 1c<101 \le c < 10 if needed.

Example
Adding with a common power of ten

Compute (3×104)+(2×103)\left(3\times 10^{4}\right) + \left(2\times 10^{3}\right).

3×104+2×103=3×104+0.2×104match the exponents=(3+0.2)×104add the coefficients=3.2×104.\begin{aligned} 3\times 10^{4} + 2\times 10^{3} &= 3\times 10^{4} + 0.2\times 10^{4} && \text{match the exponents} \\[4pt] &= (3 + 0.2)\times 10^{4} && \text{add the coefficients} \\[4pt] &= 3.2\times 10^{4}. \end{aligned}

Rewriting 2×1032\times 10^{3} as 0.2×1040.2\times 10^{4} lets both terms share 10410^{4} before adding.

Tip

Never add the powers of 1010 when you are adding numbers --- that is the rule for multiplying. For a sum, the exponents must already be equal; only the coefficients get added.

Formulas, Proofs & Tips

Tip
The exponent rules
aman=am+n,aman=amn,(am)n=amn,a0=1,an=1ana^m a^n = a^{m+n},\qquad \frac{a^m}{a^n}=a^{m-n},\qquad (a^m)^n = a^{mn},\qquad a^0 = 1,\qquad a^{-n}=\frac{1}{a^{n}}

What it means. Multiplying powers adds exponents; dividing subtracts them; a power of a power multiplies them.

Example. 2324=27=1282^3\cdot 2^4=2^7=128, and 2522=23=8\dfrac{2^5}{2^2}=2^3=8.

Why it works. amana^m a^n writes aa down mm times then nn more times — m+nm+n copies in all. Division cancels copies, leaving mnm-n. For a0a^0: amam=amm=a0\tfrac{a^m}{a^m}=a^{m-m}=a^0, and any nonzero number over itself is 11. For negatives: an=a0n=a0an=1ana^{-n}=a^{0-n}=\tfrac{a^0}{a^n}=\tfrac{1}{a^n}.

Tip. The rules only combine powers of the same base. 23322^3\cdot 3^2 does not simplify by adding exponents.