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Differential EquationsEasyThe Wronskian & Variation of Parameters

The Wronskian & Variation of Parameters · Easy problem

The equation y′′−2y′+2y=0y''-2y'+2y=0 has solutions y1=etcos⁡ty_1=e^{t}\cos t and y2=etsin⁡ty_2=e^{t}\sin t. Evaluate their Wronskian at t=ln⁡3t=\ln 3.