MathCastle
Differential EquationsChallengeThe Wronskian & Variation of Parameters

The Wronskian & Variation of Parameters · Challenge problem

The equation ty′′−(2t+1)y′+(t+1)y=t2etty''-(2t+1)y'+(t+1)y=t^2e^{t} (t>0t>0) has the homogeneous solution y1=ety_1=e^{t}. Solve it with y(1)=0y(1)=0, y′(1)=0y'(1)=0 and give y(2)y(2).