Algebra 2HardConic Sections ShareConic Sections · Hard problemConvert 9x2−16y2−90x−32y+65=09x^2 - 16y^2 - 90x - 32y + 65 = 09x2−16y2−90x−32y+65=0 to the standard form of a hyperbola, (x−h)2a2−(y−k)2b2=1\dfrac{(x-h)^2}{a^2} - \dfrac{(y-k)^2}{b^2} = 1a2(x−h)2−b2(y−k)2=1. Find a2+b2a^2 + b^2a2+b2.Check Show answer Walk through it step by step Practice more like this Review this concept