The Four Conics & Review Formulas
A conic section is a curve you get by slicing a double cone with a flat plane. Tilting the plane a little more each time produces, in order, a circle, an ellipse, a parabola, and a hyperbola. Every one of them can be written as a single second-degree equation
and the whole topic is really one question asked four ways: what shape does this equation draw, and where are its key points?
Slicing a cone gives four curves — circle, ellipse, parabola, hyperbola — and each has a defining distance property: an ellipse is the set of points whose distances to two foci sum to a constant, a hyperbola where they differ by a constant, a parabola where the distance to a focus equals the distance to a line. Completing the square turns any second-degree equation into a standard form that reveals which curve it is.
Every conic is defined by distances, which is why the distance formula is the key tool: a circle is all points at one distance from a center; an ellipse, all points whose distances to two foci add to a constant; a hyperbola, all points whose distances differ by a constant; a parabola, all points equally far from a focus and a line. Writing any of these with the distance formula and squaring produces a second-degree equation.
For points and :
The distance formula is the circle equation in disguise (a circle is all points a fixed distance from the center), so keep it close.
For and :
Reading as an ellipse with semi-axes and . The semi-axes are and .
The four conics, side by side.
Tip: A circle is just a special ellipse where both radii are equal. If you understand the ellipse deeply, the circle is free.
For and , find and the midpoint. Is on the circle with diameter ?
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. Midpoint , so the circle has center and radius . Distance from to is : yes, it is on the circle.
Circles
A circle with center and radius is the set of all points a distance from the center:
Read the center straight off the equation as the opposites of the numbers inside the parentheses, and take .
The circle equation is the distance formula with the distance fixed: a point is on the circle exactly when its distance to is , that is ; squaring gives the standard form. So the center shows up with flipped signs for the same reason a vertex does in .
For the center is (note ) and the radius is .
Reading the radius as : has radius , not .
Convert into standard form.
Group the 's and 's and move the constant:
Complete each square by adding and to both sides:
So the center is and the radius is .
Tip: When you complete the square, whatever you add on the left you must add on the right. A common slip is adding and only on one side.
Find the center and radius of .
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Group and complete squares: , so . Center , radius .
Parabolas as Conics
A parabola is every point equidistant from a fixed focus and a fixed line called the directrix. In vertex form:
Either way the vertex is : it is the turning point, halfway between the focus and the directrix.
Take the focus and the directrix . A point is equally far from both when ; squaring and simplifying leaves , or . That is why the coefficient reveals : for , and the focus is unit above the vertex.
Write an upward parabola as . Then is the distance from the vertex to the focus (and to the directrix):
The focus sits inside the curve; the directrix is the same distance out the other side.
For we have , so and . The vertex is , the parabola opens up, the focus is , and the directrix is the line .
Reading as the coefficient: for , "focus at ." The coefficient is ; setting it equal to gives , so the focus is .
Tip: An term (and no ) means the parabola opens up or down; a term (and no ) means it opens left or right. A parabola is the only conic with just one squared variable.
Find the vertex, focus and directrix of .
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Vertex . gives , and it opens up, so the focus is and the directrix is .
Ellipses
The larger denominator sits under the axis holding the major axis (the long one). Let be the larger of the two, the smaller. Then:
- Vertices: endpoints of the major axis, distance from center.
- Co-vertices: endpoints of the minor axis, distance from center.
- Foci: distance from center along the major axis, where .
A shifted ellipse uses with center .
An ellipse is all points whose distances to the two foci add to , the length of the major axis. At the top of the ellipse the two distances are equal, each , and they form a right triangle with legs and ; so , which is where comes from. For : .
Analyze .
The larger denominator () is under , so the major axis is horizontal with and . Then , so .
- Center ; Vertices ; Co-vertices ; Foci .
Using the hyperbola relation: , putting the foci outside the ellipse at . For an ellipse the foci are inside: .
Tip: For an ellipse and the foci hug the long axis, so always. If you ever get , you mislabeled and .
For , find the orientation, vertices, co-vertices and foci.
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The larger denominator, , is under : the major axis is vertical, , . Vertices , co-vertices . , so foci .
Hyperbolas
The positive term tells you which way it opens; is always the number under the positive term.
- Vertices: distance from center, on the opening axis.
- Foci: distance from center, where (note the !).
- Asymptotes: for they are ; for the up–down form they are .
Far from the center, the in becomes negligible next to the squared terms, so the curve nearly satisfies , the lines . Those are the asymptotes, the diagonals of the -by- box. The foci lie beyond the vertices, and is the box's half-diagonal: .
Analyze .
The term is positive, so it opens left–right with and . Then , so .
- Center ; Vertices ; Foci ; Asymptotes .
Taking the asymptote slopes upside down: for . The slope is rise over run of the box, .
Tip: Ellipse uses ; hyperbola uses . For a hyperbola the foci are farther out than the vertices, so .
For , find the direction it opens, the vertices, the foci and the asymptotes.
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The term is positive, so it opens up and down; , . Vertices . , foci . Asymptotes .
Identifying a Conic from General Form
Given (no term), look only at and :
- Circle: (same coefficient on and ).
- Parabola: exactly one of is (only one squared term).
- Ellipse: but and have the same sign.
- Hyperbola: and have opposite signs.
Completing the square never changes the and coefficients, so they already decide the shape: equal coefficients give a circle, same signs give an ellipse, opposite signs a hyperbola, and a missing square a parabola. The linear terms only move the center.
- : circle.
- (only ): parabola.
- : same sign, unequal ellipse.
- : opposite signs hyperbola.
Calling an ellipse because its coefficients are not . Equal and coefficients make a circle: dividing by gives .
Tip (how to tell them apart at a glance): One squared term parabola. Two squared terms: same number circle, added ellipse, subtracted hyperbola.
Classify , and .
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Opposite signs on the squares: hyperbola. Only : parabola. Equal coefficients: circle (radius ).
Applications (light)
- Ellipses — orbits: planets and satellites travel in ellipses with the larger body at one focus (Kepler's First Law).
- Ellipses — whispering galleries: a sound starting at one focus reflects off the elliptical ceiling and gathers at the other focus, so a whisper carries across the room.
- Parabolas — dishes and headlights: a satellite dish or reflector collects incoming rays at its focus (and a bulb at the focus sends out a straight beam).
- Hyperbolas — navigation and comets: some comets swing past the sun on an open hyperbolic path and never return.
Each application uses a conic's focus. A parabolic dish sends every incoming parallel ray to its focus because each point is as far from the focus as from the directrix, which makes the reflection angles equal. An ellipse reflects any ray from one focus to the other, which is why a whisper at one focus is heard at the other.
Tip: The focus is the star of every application. Ellipses and hyperbolas have two foci; a parabola has one. That reflecting property is exactly why the focus matters.
Placing a satellite dish's receiver at the vertex. Signals concentrate at the focus: for a dish (in inches), , so the receiver goes inches above the vertex.
A satellite dish is in across and in deep. Where should the receiver be placed?
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Model it as through : , so and . The receiver goes at the focus, in above the vertex.
Going Deeper: Advanced Conics
So far you have read a conic off its equation. The reverse skill — constructing the equation from geometric conditions — is what real problems ask for. Each unknown coefficient needs one condition:
- Through given points: plug each point into the general form and solve the resulting linear system for the coefficients.
- Given foci and eccentricity: the foci fix the center and ; then gives , and comes from (ellipse) or (hyperbola).
- Given a tangent line: impose the tangency condition (next box) as one more equation.
Eccentricity measures how “stretched” a conic is: circle, ellipse, parabola, hyperbola.
Find the ellipse centered at the origin with foci and eccentricity .
The foci are on the -axis at distance , so the major axis is horizontal. From ,
Recompute using :
So the ellipse is
with vertices , co-vertices , and foci as required.
To find where a line meets a conic, substitute the line into the conic. You get a quadratic in one variable, so the discriminant of that quadratic tells you everything:
So “the line is tangent to the conic” translates into the single algebraic equation . For the ellipse this collapses to the tidy rule: the line is tangent exactly when
For which values of is the line tangent to ?
Substitute and clear the fraction (multiply by ):
Expand into a quadratic in :
Set its discriminant to zero:
so and . Checking against the shortcut with , , : . ✓
A focal chord is any chord through a focus. The special focal chord perpendicular to the major (or focal) axis is the latus rectum, and its length measures how “wide” the curve is at the focus:
The reflection property explains every application from Section 7: a ray aimed at one focus of an ellipse bounces to the other focus; a ray parallel to a parabola's axis reflects through its single focus; and a ray toward one focus of a hyperbola reflects away along the line to the other focus.
For we have , , so each latus rectum has length
Since the foci are , the latus-rectum endpoints above and below the right focus are .
When an term is present the conic is rotated, and reading vs. is no longer enough. The general equation
is classified by the invariant :
This quantity is unchanged by any rotation of the axes, which is why it works even when . (When it agrees with the sign test of Section 6.)
Classify . Here , , , so
an ellipse (tilted, since ). By contrast gives , a parabola.
A “conic” equation does not always draw a smooth curve. When the slicing plane passes through the apex of the cone you get a degenerate conic:
- A single point — e.g. is only (a “circle of radius ”).
- One line / two parallel lines — e.g. gives (a degenerate parabola).
- Two intersecting lines — e.g. gives (a degenerate hyperbola).
- Empty set (no points) — e.g. has no real solutions.
Watch for these after completing the square: a right-hand side of or a negative number is the tell.
The closest point on a conic to an external point has a clean geometric signature: the segment is perpendicular to the tangent line at (it lies along the normal). For a circle this makes the answer immediate — the nearest point lies on the line through and the center:
where is the center and the radius. For other conics you either minimize the squared distance with calculus or impose the normal condition and solve.
Find the shortest distance from to the circle .
The center is and . The distance from to the center is
Since is outside the circle (), the shortest distance is
reached at the point where the segment crosses the circle.
Tip: Discriminants run this whole section. (from the equation) tells you which conic; the discriminant of the substituted quadratic (from a line-plus-conic) tells you how a line meets it. Same tool, two jobs.
Write the equation of the circle with center and radius .
Work it on paper before revealing the answer.
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Answer: .
Why It Works
Start from the definition of an ellipse, with foci at , write the distances with the distance formula, isolate one radical, square, isolate again, square again, and the equation collapses to with . The same computation with a minus sign yields the hyperbola. The "focus–directrix" definition of a parabola gives in one squaring — which is why a parabolic mirror focuses parallel light at its focus.
Do not read a proof the way you read a rule. Cover the last line, ask what the previous line forces, and only then uncover it. If a step feels like magic, that is the step to work by hand with a concrete number.
Formulas, Proofs & Tips
What it means. All points at distance from the centre .
Example. Center , radius : .
Why it works. A circle is by definition the set of points a fixed distance from the centre. Writing that distance with the distance formula gives ; squaring both sides removes the root.
Tip. Given , complete the square in and in to recover the centre and radius.