AIMEHardOlympiad Geometry ShareOlympiad Geometry · Hard problemTriangle ABCABCABC has BC=9BC = 9BC=9, CA=10CA = 10CA=10 and AB=17AB = 17AB=17. The median from AAA has length pqr\tfrac{p\sqrt{q}}{r}rpq, where qqq is squarefree and gcd(p,r)=1\gcd(p, r) = 1gcd(p,r)=1. Find p+q+rp + q + rp+q+r.Check Show answer Walk through it step by step Practice more like this Review this concept