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AIMEHardOlympiad Geometry

Olympiad Geometry · Hard problem

Triangle ABCABC has BC=13BC = 13, CA=14CA = 14 and AB=15AB = 15. The median from AA has length pqr\tfrac{p\sqrt{q}}{r}, where qq is squarefree and gcd⁡(p,r)=1\gcd(p, r) = 1. Find p+q+rp + q + r.