AIMEHardOlympiad Geometry ShareOlympiad Geometry · Hard problemTriangle ABCABCABC has BC=13BC = 13BC=13, CA=14CA = 14CA=14 and AB=15AB = 15AB=15. The median from AAA has length pqr\tfrac{p\sqrt{q}}{r}rpq, where qqq is squarefree and gcd(p,r)=1\gcd(p, r) = 1gcd(p,r)=1. Find p+q+rp + q + rp+q+r.Check Show answer Walk through it step by step Practice more like this Review this concept