AIMEHardOlympiad Geometry ShareOlympiad Geometry · Hard problemTriangle ABCABCABC has BC=12BC = 12BC=12, CA=19CA = 19CA=19 and AB=23AB = 23AB=23. The median from AAA has length pqr\tfrac{p\sqrt{q}}{r}rpq, where qqq is squarefree and gcd(p,r)=1\gcd(p, r) = 1gcd(p,r)=1. Find p+q+rp + q + rp+q+r.Check Show answer Walk through it step by step Practice more like this Review this concept