GeometryMediumOlympiad Geometry ShareOlympiad Geometry · Medium problemIn △ABC\triangle ABC△ABC, AB=ACAB = ACAB=AC and ∠A=40∘\angle A = 40^\circ∠A=40∘. Point DDD lies on side AC‾\overline{AC}AC so that BD=BCBD = BCBD=BC. Find ∠ABD\angle ABD∠ABD.Check Show answer Walk through it step by step Practice more like this Review this concept