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GeometryMediumOlympiad Geometry

Olympiad Geometry · Medium problem

Ray OBOB bisects ∠AOC\angle AOC. If ∠AOB=(3x+18)∘\angle AOB = (3x+18)^\circ and ∠AOC=(10x)∘\angle AOC = (10x)^\circ, and ray ODOD is the opposite ray of ray OAOA, find ∠BOD\angle BOD.