GeometryMediumOlympiad Geometry ShareOlympiad Geometry · Medium problemRay OBOBOB bisects ∠AOC\angle AOC∠AOC. If ∠AOB=(3x+18)∘\angle AOB = (3x+18)^\circ∠AOB=(3x+18)∘ and ∠AOC=(10x)∘\angle AOC = (10x)^\circ∠AOC=(10x)∘, and ray ODODOD is the opposite ray of ray OAOAOA, find ∠BOD\angle BOD∠BOD.Check Show answer Walk through it step by step Practice more like this Review this concept