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GeometryMediumOlympiad Geometry

Olympiad Geometry · Medium problem

In △ABC\triangle ABC, the bisector of ∠A\angle A meets BC‾\overline{BC} at DD. Given AB=8AB=8, AC=12AC=12, and BC=15BC=15, use the angle-bisector proportion BDDC=ABAC\dfrac{BD}{DC}=\dfrac{AB}{AC} to find BDBD and DCDC.