Algebra 2ChallengeTelescoping & Recursion ShareTelescoping & Recursion · Challenge problemEvaluate 11⋅2⋅3+12⋅3⋅4+⋯+18⋅9⋅10\dfrac{1}{1 \cdot 2 \cdot 3} + \dfrac{1}{2 \cdot 3 \cdot 4} + \cdots + \dfrac{1}{8 \cdot 9 \cdot 10}1⋅2⋅31+2⋅3⋅41+⋯+8⋅9⋅101 as a common fraction.Check Show answer Walk through it step by step Practice more like this Review this concept