CalculusChallengeTechniques of Integration ShareTechniques of Integration · Challenge problemEvaluate ∫1x(x+1) dx\displaystyle\int \frac{1}{\sqrt{x} \left(x + 1\right)}\,dx∫x(x+1)1dx for x>0x > 0x>0.Check Show answer Walk through it step by step Practice more like this Review this concept