MathCastle
ChallengeMediumTelescoping & Recursion

Telescoping & Recursion · Medium problem

A sequence is defined by a1=1a_1 = 1 and an+1=an1+3ana_{n+1} = \dfrac{a_n}{1 + 3a_n} for n≥1n \ge 1. Find the value of ∑n=133anan+1\displaystyle\sum_{n=1}^{33} a_n a_{n+1}.

Express your answer as a common fraction.