ChallengeMediumTelescoping & Recursion ShareTelescoping & Recursion · Medium problemEvaluate ∑n=1999log10 (1+1n)\displaystyle\sum_{n=1}^{999}\log_{10}\!\left(1+\dfrac{1}{n}\right)n=1∑999log10(1+n1).Check Show answer Walk through it step by step Practice more like this Review this concept