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Algebra 2SuperchallengeRational Expressions & Functions

Rational Expressions & Functions · Superchallenge problem

Write 1n(n+1)\dfrac{1}{n(n+1)} as a difference of two simple fractions, then evaluate ∑n=1991n(n+1)\displaystyle\sum_{n=1}^{99}\dfrac{1}{n(n+1)}.