Algebra 2SuperchallengeRational Expressions & Functions ShareRational Expressions & Functions · Superchallenge problemWrite 1n(n+1)\dfrac{1}{n(n+1)}n(n+1)1 as a difference of two simple fractions, then evaluate ∑n=1991n(n+1)\displaystyle\sum_{n=1}^{99}\dfrac{1}{n(n+1)}n=1∑99n(n+1)1. Show answer Walk through it step by step Practice more like this Review this concept