Algebra 1ChallengeExponents ShareExponents · Challenge problemSimplify (positive exponents only): (−3a−1b22a2b−1)3\;\left(\dfrac{-3a^{-1}b^{2}}{2a^{2}b^{-1}}\right)^{3}(2a2b−1−3a−1b2)3.A−27b98a10-\dfrac{27b^{9}}{8a^{10}}−8a1027b9B−8a927b9-\dfrac{8a^{9}}{27b^{9}}−27b98a9C−27b98a9-\dfrac{27b^{9}}{8a^{9}}−8a927b9D−27b108a9-\dfrac{27b^{10}}{8a^{9}}−8a927b10Check Show answer Walk through it step by step Practice more like this Review this concept