TrigonometryHardTrigonometric Equations ShareTrigonometric Equations · Hard problemSolve −sin(x)−cos(2x)=0- \sin{\left(x \right)} - \cos{\left(2 x \right)} = 0−sin(x)−cos(2x)=0 for xxx on [0,2π)[0, 2\pi)[0,2π). Enter the solutions in increasing order, one per box. Show answer Walk through it step by step Practice more like this Review this concept