TrigonometryHardTrigonometric Equations ShareTrigonometric Equations · Hard problemSolve cscx=−233\csc x=-\dfrac{2\sqrt{3}}{3}cscx=−323 on [0,2π)[0,2\pi)[0,2π).Ax=34π, 5π3x=\dfrac{3}{4\pi},\ \dfrac{5\pi}{3}x=4π3, 35πBx=8π3, 5π3x=\dfrac{8\pi}{3},\ \dfrac{5\pi}{3}x=38π, 35πCx=4π3, 5π3x=\dfrac{4\pi}{3},\ \dfrac{5\pi}{3}x=34π, 35πDx=4π3, 5π4x=\dfrac{4\pi}{3},\ \dfrac{5\pi}{4}x=34π, 45πCheck Show answer Walk through it step by step Practice more like this Review this concept