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TrigonometryHardTrigonometric Equations

Trigonometric Equations · Hard problem

Solve cos⁡2x+3sin⁡x−2=0\cos 2x+3\sin x-2=0 on [0,2π)[0,2\pi). (Hint: cos⁡2x=1−2sin⁡2x\cos 2x=1-2\sin^2 x.)