TrigonometryEasyTrigonometric Equations ShareTrigonometric Equations · Easy problemSolve tanx (tanx−1)=0\tan x\,(\tan x - 1) = 0tanx(tanx−1)=0 on [0,2π)[0,2\pi)[0,2π).Ax=0, 4π, π, 5π4x=0,\ \dfrac{4}{\pi},\ \pi,\ \dfrac{5\pi}{4}x=0, π4, π, 45πBx=0, π4, π, 5π3x=0,\ \dfrac{\pi}{4},\ \pi,\ \dfrac{5\pi}{3}x=0, 4π, π, 35πCx=0, π4, π, 5π4x=0,\ \dfrac{\pi}{4},\ \pi,\ \dfrac{5\pi}{4}x=0, 4π, π, 45πDx=0, π4, π, 5π5x=0,\ \dfrac{\pi}{4},\ \pi,\ \dfrac{5\pi}{5}x=0, 4π, π, 55πCheck Show answer Walk through it step by step Practice more like this Review this concept