TrigonometrySuperchallengeTrigonometric Equations ShareTrigonometric Equations · Superchallenge problemSolve 6sin2x−sinx−1=06\sin^2 x-\sin x-1=06sin2x−sinx−1=0 on [0,2π)[0,2\pi)[0,2π); round non-special values to three decimals.Check Show answer Walk through it step by step Practice more like this Review this concept