TrigonometrySuperchallengeTrigonometric Equations ShareTrigonometric Equations · Superchallenge problemSolve 3sin2x−sinx−1=03\sin^2 x-\sin x-1=03sin2x−sinx−1=0 on [0,2π)[0,2\pi)[0,2π); round to three decimals.Check Show answer Walk through it step by step Practice more like this Review this concept