TrigonometryChallengeTrigonometric Equations ShareTrigonometric Equations · Challenge problem1Solve sinx−cosx=1\sin x-\cos x=1sinx−cosx=1 on [0,2π)[0,2\pi)[0,2π) using the amplitude form.Ax=π3, πx=\tfrac{\pi}{3},\ \pix=3π, πBx=π4, πx=\tfrac{\pi}{4},\ \pix=4π, πCx=2π, πx=\tfrac{2}{\pi},\ \pix=π2, πDx=π2, πx=\tfrac{\pi}{2},\ \pix=2π, πCheck Show answer Walk through it step by step Practice more like this Review this concept