TrigonometryEasyGraphs of the Other Trigonometric Functions ShareGraphs of the Other Trigonometric Functions · Easy problemGive one vertical asymptote of y=sec(2x)y=\sec(2x)y=sec(2x). (Set 2x=π22x=\dfrac{\pi}{2}2x=2π and solve.)Aπ4+nπ2\dfrac{\pi}{4}+\dfrac{n\pi}{2}4π+2nπBπ4+nπ3\dfrac{\pi}{4}+\dfrac{n\pi}{3}4π+3nπC4π+nπ2\dfrac{4}{\pi}+\dfrac{n\pi}{2}π4+2nπDπ4−nπ2\dfrac{\pi}{4}-\dfrac{n\pi}{2}4π−2nπCheck Show answer Walk through it step by step Practice more like this Review this concept