TrigonometryHard ShareTrigonometry · Hard problemSimplify sin(−θ) cos(−θ)cot(−θ)\dfrac{\sin(-\theta)\,\cos(-\theta)}{\cot(-\theta)}cot(−θ)sin(−θ)cos(−θ) to a single power of one function.Asin3θ\sin^3\thetasin3θBsin2θ\sin^2\thetasin2θCsin4θ\sin^4\thetasin4θD−sin2θ-\sin^2\theta−sin2θCheck Show answer Walk through it step by step Practice more like this