TrigonometryChallenge ShareTrigonometry · Challenge problemIf cotθ=52\cot\theta=\dfrac{\sqrt{5}}{2}cotθ=25, find the exact value of csc2θ−sec2θcsc2θ+sec2θ\dfrac{\csc^2\theta-\sec^2\theta}{\csc^2\theta+\sec^2\theta}csc2θ+sec2θcsc2θ−sec2θ.Check Show answer Walk through it step by step Practice more like this