TrigonometryMedium ShareTrigonometry · Medium problemWrite the double-angle formula for cos(2θ)\cos(2\theta)cos(2θ) in terms of cosθ\cos\thetacosθ only.A2cos2θ+12\cos^2\theta+12cos2θ+1B2cos2θ−22\cos^2\theta-22cos2θ−2C2cos3θ−12\cos^{3}\theta-12cos3θ−1D2cos2θ−12\cos^2\theta-12cos2θ−1Check Show answer Walk through it step by step Practice more like this