Algebra 2HardSystems of Equations

Systems of Equations · Hard problem

This is a linear system in disguise. Solve for $x$ and $y$ .

\begin{aligned} \dfrac{2}{x} + \dfrac{1}{y} = 0 \\ \dfrac{3}{x} - \dfrac{1}{y} = - \dfrac{5}{4} \end{aligned}