Algebra 2HardSystems of Equations

Systems of Equations · Hard problem

This is a linear system in disguise. Solve for $x$ and $y$ .

\begin{aligned} \dfrac{2}{x} + \dfrac{4}{y} = \dfrac{10}{3} \\ \dfrac{1}{x} - \dfrac{5}{y} = - \dfrac{2}{3} \end{aligned}