Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemThis is a linear system in disguise. Solve for xxx and yyy.5x+3y=−142x−1y=1\begin{aligned} \dfrac{5}{x} + \dfrac{3}{y} = - \dfrac{1}{4} \\ \dfrac{2}{x} - \dfrac{1}{y} = 1 \end{aligned}x5+y3=−41x2−y1=1 Show answer Walk through it step by step Practice more like this Review this concept