Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve for xxx and yyy.5x⋅2y=2005x2y=258\begin{aligned} 5^{x} \cdot 2^{y} = 200 \\ \dfrac{5^{x}}{2^{y}} = \dfrac{25}{8} \end{aligned}5x⋅2y=2002y5x=825 Show answer Walk through it step by step Practice more like this Review this concept