Algebra 1HardSystems of Equations ShareSystems of Equations · Hard problemHow many solutions does this system have?{3x+2y=56x+4y=10\begin{cases} 3 x + 2 y = 5 \\ 6 x + 4 y = 10 \end{cases}{3x+2y=56x+4y=10Aexactly one solutionBinfinitely many solutionsCno solutionCheck Show answer Walk through it step by step Practice more like this Review this concept