MathCastle
Algebra 1HardSystems of Equations

Systems of Equations · Hard problem

Solve the system for xx and yy.

{−2x5+3y4=320x6+2y3=−3\begin{cases} - \frac{2 x}{5} + \frac{3 y}{4} = \frac{3}{20} \\ \frac{x}{6} + \frac{2 y}{3} = -3 \end{cases}