Algebra 1HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx and yyy.{−2x5+3y4=320x6+2y3=−3\begin{cases} - \frac{2 x}{5} + \frac{3 y}{4} = \frac{3}{20} \\ \frac{x}{6} + \frac{2 y}{3} = -3 \end{cases}{−52x+43y=2036x+32y=−3 Show answer Walk through it step by step Practice more like this Review this concept