Algebra 1HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx and yyy.{2x3+y5=10415x4+3y5=345\begin{cases} \frac{2 x}{3} + \frac{y}{5} = \frac{104}{15} \\ \frac{x}{4} + \frac{3 y}{5} = \frac{34}{5} \end{cases}{32x+5y=151044x+53y=534 Show answer Walk through it step by step Practice more like this Review this concept