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Algebra 1HardSystems of Equations

Systems of Equations · Hard problem

Solve the system for xx and yy.

{2x3+y5=10415x4+3y5=345\begin{cases} \frac{2 x}{3} + \frac{y}{5} = \frac{104}{15} \\ \frac{x}{4} + \frac{3 y}{5} = \frac{34}{5} \end{cases}